Alvin and Dalton each made a bowl of punch. Dalton used 2 times as much lemonade as Alvin did. If Alvin used 3 1/6 cups of lemonade, how many cups of lemonade did Dalton use?

Write your answer as a fraction or as a whole or mixed number.

cups

1 answer

To determine how many cups of lemonade Dalton used, we start with the amount that Alvin used. Alvin used \( 3 \frac{1}{6} \) cups of lemonade.

First, we convert \( 3 \frac{1}{6} \) to an improper fraction:

\[ 3 \frac{1}{6} = \frac{3 \times 6 + 1}{6} = \frac{18 + 1}{6} = \frac{19}{6} \]

Dalton used 2 times as much lemonade as Alvin. Therefore, we need to calculate:

\[ 2 \times \frac{19}{6} = \frac{2 \times 19}{6} = \frac{38}{6} \]

Now, we simplify \( \frac{38}{6} \):

\[ \frac{38}{6} = \frac{19}{3} \]

Next, we can convert \( \frac{19}{3} \) to a mixed number:

\[ \frac{19}{3} = 6 \frac{1}{3} \]

Therefore, the amount of lemonade Dalton used is

\[ \boxed{6 \frac{1}{3}} \text{ cups.} \]