ALuminum can be determined gravimetricaly by the reaction with solution of 8-hydroxyquinoline (C9H7NO3).The net ionic equation . A mass of 0.1248g of Al(C9H6NO)3 WAS obtained by precipitating all of the the Al3+ from a solution prepared by dissolving 1.8571g of a mineral. what is the mass percent of alumininum in the mineral sample

Answer 1

Now, for every mole of Al(C9H6NO)3, there is 1 mole of Al^3+. i.e., 1 mole of Al=1 mole of Al(C9H6NO)3

Al(C9H6NO)3 *(1 mole/459.4317 g)= moles of Al(C9H6NO)3

moles of Al(C9H6NO)3=moles of Al^3+

moles of Al^3+*(26.98g/1 mole)= mass of Al^3+ in grams

(mass of Al^3+ in grams/1.8571g)*100=mass percent of Al^3+ in the mineral sample

***Answer contains no more and no less than four significant figures.

Answer 2

@@Look for correction.

Now, for every mole of Al(C9H6NO)3, there is 1 mole of Al^3+. i.e., 1 mole of Al=1 mole of Al(C9H6NO)3

@@0.1248g of Al(C9H6NO)3 *(1 mole/459.4317 g)= moles of Al(C9H6NO)3

moles of Al(C9H6NO)3=moles of Al^3+

moles of Al^3+*(26.98g/1 mole)= mass of Al^3+ in grams

(mass of Al^3+ in grams/1.8571g)*100=mass percent of Al^3+ in the mineral sample

***Answer contains no more and no less than four significant figures.