AlBr3 + 3NaOH ==> Al(OH)3 + 3NaBr
1.55 mols AlBr3 x (32 mols NaBr/1 mol AlBr3) = 1.55 x 3/1 = ?
You do part b the same way. Use the coefficients in the balanced equation to convert what you have to what you want; i.e., to convert anything to anything.
Aluminum bromide and sodium hydroxide react to form aluminum hydroxide and sodium bromide.
a.)How many moles of sodium bromide can be formed from 1.55 moles of aluminum bromide?
b.)How many moles of aluminum hydroxide may be formed from 4.65 moles of sodium hydroxide?
2 answers
Aluminum bromide, Al(Br)3, and sodium hydroxide, NaOH, react to form aluminum hydroxide, Al(OH)3, and sodium bromide, NaBr.
a) How many moles of sodium bromide can be formed from 1.55 moles of aluminum bromide?
a) How many moles of sodium bromide can be formed from 1.55 moles of aluminum bromide?
1 answer