HBr + NaO ==> NaBr + H2O
This is a limiting reagent (LR) problem and you know that because amounts are given for BOTH reactants.
mols HBr = grams/molar mass = ?
mols NaOH = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols HBr to mols H2O.
Do the same for mols NaOH to mols H2O.
It is likely that the two values for mols H2O will not be the same which means one of them is wrong; the correct value in LR problems is ALWAYS the smaller one and the reagent responsible for that value is the LR.
Now convert mols H2O to g. g = mols x molar mass.
Aqueous hydrobromic acid will react with solid sodium hydroxide to produce aqueous sodium bromide and liquid water . Suppose 4.05 g of hydrobromic acid is mixed with 0.86 g of sodium hydroxide. Calculate the maximum mass of water that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits.
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