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Original Question
Hank has three pieces of wood. Board A is 7 inches long, board B is 13 inches long, and board C is 5 inches long. If the full l...Asked by drakeboing
                Alfred has three pieces of wood. Board A is 11 inches long, board B is 4 inches long, and board C is 6 inches long. If the full length of each board is used, can the three pieces of wood be placed together to form a triangle?
A.
yes, 4 + 6 < 11
B.
no, 11 - 4 < 6
C.
no, 4 + 6 < 11
D.
yes, 11 - 6 > 4
            
        A.
yes, 4 + 6 < 11
B.
no, 11 - 4 < 6
C.
no, 4 + 6 < 11
D.
yes, 11 - 6 > 4
Answers
                                                    There are no human answers yet.
                                            
                
                    Answered by
            GPT-4o mini
            
    To determine if three lengths can form a triangle, we can use the triangle inequality theorem. This theorem states that for any three sides \( a \), \( b \), and \( c \) of a triangle, the following conditions must be true:
1. \( a + b > c \)
2. \( a + c > b \)
3. \( b + c > a \)
In this case, the lengths of the boards are:
- Board A: 11 inches (let's denote it as \( a \))
- Board B: 4 inches (let's denote it as \( b \))
- Board C: 6 inches (let's denote it as \( c \))
Now we will check the three inequalities:
1. \( a + b > c \):
\( 11 + 4 > 6 \)
\( 15 > 6 \) (True)
2. \( a + c > b \):
\( 11 + 6 > 4 \)
\( 17 > 4 \) (True)
3. \( b + c > a \):
\( 4 + 6 > 11 \)
\( 10 > 11 \) (False)
Since the third condition \( b + c > a \) is false (10 is not greater than 11), the three pieces of wood cannot be arranged to form a triangle.
Thus, the correct answer is:
C. no, 4 + 6 < 11
    
1. \( a + b > c \)
2. \( a + c > b \)
3. \( b + c > a \)
In this case, the lengths of the boards are:
- Board A: 11 inches (let's denote it as \( a \))
- Board B: 4 inches (let's denote it as \( b \))
- Board C: 6 inches (let's denote it as \( c \))
Now we will check the three inequalities:
1. \( a + b > c \):
\( 11 + 4 > 6 \)
\( 15 > 6 \) (True)
2. \( a + c > b \):
\( 11 + 6 > 4 \)
\( 17 > 4 \) (True)
3. \( b + c > a \):
\( 4 + 6 > 11 \)
\( 10 > 11 \) (False)
Since the third condition \( b + c > a \) is false (10 is not greater than 11), the three pieces of wood cannot be arranged to form a triangle.
Thus, the correct answer is:
C. no, 4 + 6 < 11
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