Asked by Anonymous
again.. im lost with finding slope intercept and standard form of this equation as well.
x intercept =2, y intercept= -4
x intercept =2, y intercept= -4
Answers
Answered by
Reiny
aren't you just given the two points
(2,0) and (0,-4) ?
from that you can find the slope
= (-4-0)/(0-2) = 2
so in y= mx+b you now know m and b
to give you
y = 2x - 4
which can be rearranged to
2x - y = 4
there is another very easy way to find the equation of a straight line if you know the x-intercept 'a' and the y-intercept 'b'
the equation is
x/a + y/b = 1
so here x/2 + y/-4 = 1
multiply by 4 to get
2x - y = 4 (just as above)
(2,0) and (0,-4) ?
from that you can find the slope
= (-4-0)/(0-2) = 2
so in y= mx+b you now know m and b
to give you
y = 2x - 4
which can be rearranged to
2x - y = 4
there is another very easy way to find the equation of a straight line if you know the x-intercept 'a' and the y-intercept 'b'
the equation is
x/a + y/b = 1
so here x/2 + y/-4 = 1
multiply by 4 to get
2x - y = 4 (just as above)
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