since loga + logb = log(ab) we have
4(ln(z(z+5)) = ln (z(z+5))^4
2ln(z-5) = ln (z-5)^2
Now, since loga - logb = log(a/b), we have
ln ( (z(z+5))^4 / (z-5)^2 )
Hi! I'm really lost on how to do this. Does anyone know how to solve this? Thanks! :)
Condesne the expression to the logarithm of a single quanity.
4(lnz+ln(z+5)]-2ln(z-5)
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