After you pick up a spare, your bowling ball rolls without slipping back toward the ball rack with a linear speed of v = 3.27 m/s

Question

To reach the rack, the ball rolls up a ramp that rises through a vertical distance of h = 0.572 m. What is the linear speed of the ball when it reaches the top of the ramp?

Answer 1

KE=PE
KE= KE(transl) +KE(rot) =
=m•v²/2+Iω²/2=
= m•v²/2+ (2mR²)• v²/5•2•R²=
= m•v²/2+ mv²/5 =0.7 mv²

0.7•m•v²=mgh
v=sqrt(g•h/0.7)

Answer 2

That is exactly the way I have been doing this problem and I keep getting the wrong answer. I keep getting 2.831 m/s