Did you draw a diagram? review your basic trig functions? If so, then it should be clear that the answer is
147.0 cos 48°47'
After leaving port, a ship sails 147.0 km in the direction N48o47'E.
How far North of the port is the ship now located? (report your final answer to one decimal place)
2 answers
Direction = 48.78 Degrees E. of N.
Disp. = 147km[48.78] = 147*sin48.78 + 147*cos48.78i
Disp. = 110.6 + 96.9i.
d = 96.9 km north of port.
Disp. = 147km[48.78] = 147*sin48.78 + 147*cos48.78i
Disp. = 110.6 + 96.9i.
d = 96.9 km north of port.
2 answers