Calculate the momentum change due to the bounce.
Then use the relation:
Impulse = (avg. force)*(time) = momentum change
After falling from rest at a height of 29.2 m, a 0.488 kg ball rebounds upward, reaching a height of 20.3 m. If the contact between ball and ground lasted 1.68 ms, what average force was exerted on the ball?
I'm so confused on where to start. tyvm
3 answers
What do you mean by momentum? F=ma? thanks so much sorry to bother you
So glad someone is confused as I am! There are a lot of things on here that will not give you the write answer, but this will come pretty darn close!
There are four main calculations you need to make:
1) Find Velocity after falling (V1)
2) Find velocity on the way up again (V2)
3) Find the momentum change
4) Since (avg force)*(time)=momentum change, divide the change in momentum (found in #3) by the time to get average force.
DO NOT FORGET TO CHANGE YOUR TIME INTO SECONDS (divide ms by 1000).
For 1 & 2, use kinematic equation:
squarert: (2*9.8*Height) [9.8=gravitational acceleration]
For 3, use: m*(V1=V2)
For 4, use: momentum change/time in seconds
Hope this helps someone in the future!
There are four main calculations you need to make:
1) Find Velocity after falling (V1)
2) Find velocity on the way up again (V2)
3) Find the momentum change
4) Since (avg force)*(time)=momentum change, divide the change in momentum (found in #3) by the time to get average force.
DO NOT FORGET TO CHANGE YOUR TIME INTO SECONDS (divide ms by 1000).
For 1 & 2, use kinematic equation:
squarert: (2*9.8*Height) [9.8=gravitational acceleration]
For 3, use: m*(V1=V2)
For 4, use: momentum change/time in seconds
Hope this helps someone in the future!
1 answer