Ask a New Question

Question

After falling from rest from a height of 34 m, a 0.47 kg ball rebounds upward, reaching a height of 24 m. If the contact between ball and ground lasted 1.8 ms, what average force was exerted on the ball?
15 years ago

Answers

bobpursley
the velocity of the ball at the ground was

vf^2=2gh

vf=sqrt 2gh.

but this velocity reversed at impact, so the change in velocity is
2sqrt2gh

force*time=2sqrt(2gh)
15 years ago

Related Questions

A ball falling from rest is located 45 m below its starting point 3.0 s later. Assuming that its ac... After falling from rest at a height of 29.2 m, a 0.488 kg ball rebounds upward, reaching a height of... After falling for 15.38 s a skydiver reaches terminal speed. If the skydiver is falling straight dow... An object at rest blank at rest unless acted on by an blank force Which of the falling uses a correct formula to find the approximate? They're conference of a circle... What happens when a falling object reaches terminal velocity?(1 point) Responses The U.S. is Falling Behind in Education Evidence shows that the United States is not investing in h... The U.S. is Falling Behind in Education Evidence shows that the United States is not investing in h... Rest Name Rest Symbol Duration Note Name Note Symbol whole rest A whole rest is shown. It looks... What happens when a falling object reaches terminal velocity?(1 point) Responses It hits the gro...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use