Adult tickets to the fall play cost $6

Question

and student tickets cost $3
. The drama class sold 25
more student tickets than adult tickets to the fall play. If the class collected $660
from ticket sales, how many student tickets were sold?

The drama class sold blank student tickets.

Answer 1

Let the number of adult tickets sold be \( x \). Then, the number of student tickets sold can be expressed as \( x + 25 \) (since the class sold 25 more student tickets than adult tickets).

The total revenue from ticket sales can be expressed with the following equation:

\[ 6x + 3(x + 25) = 660 \]

Now, we can simplify and solve this equation step by step:

1. Distribute the \( 3 \) in the equation:

\[ 6x + 3x + 75 = 660 \]

2. Combine like terms:

\[ 9x + 75 = 660 \]

3. Subtract \( 75 \) from both sides:

\[ 9x = 660 - 75 \] \[ 9x = 585 \]

4. Divide both sides by \( 9 \):

\[ x = \frac{585}{9} \] \[ x = 65 \]

Now that we have \( x \), the number of adult tickets sold, we can find the number of student tickets sold:

\[ x + 25 = 65 + 25 = 90 \]

Therefore, the drama class sold 90 student tickets.