Let a be the number of adult tickets and s be the number of student tickets. We know that a = s + 20 and 8a + 4s = 880.
Substituting the first equation into the second equation, we get 8(s + 20) + 4s = 880.
Distributing through the parentheses, we get 8s + 160 + 4s = 880
Combining like terms, we get 12s + 160 = 880
Subtracting 160 from both sides, we get 12s = 720
Dividing both sides by 12, we get s = 60
Substituting this value back into the equation a = s + 20, we get a = 60 + 20 = 80. Answer: \boxed{80}.
Adult tickets to the fall play cost $8 and student tickets cost $4. The drama class sold 20 more adult tickets than student tickets to the fall play. If the class collected $880 from ticket sales, how many adult tickets were sold?
1 answer