Adding 1.530x10^3 J of electrical energy to a constant-pressure calorimeter changes the water temperature from 20.50C to 21.85C. When 1.75g of a solid salt is dissolved in the water, the temperature falls from 21.85C to 21.44C. Find the value of qp for the solution process.

Answer 1

1530 = Ccal*delta T
1530 = Ccal*(21.85-20.5)
Ccal = ?

q = Ccal*delta T salt.
q = Ccal from above x (delta T)