Add the polynomial expressions 2r ^ 2 - 3r + 4 and - 2r ^ 2 + 3r + 6 (1 point)

Answer 1

To add the polynomial expressions \(2r^2 - 3r + 4\) and \(-2r^2 + 3r + 6\), you combine like terms:

1. Combine the \(r^2\) terms: \[ 2r^2 + (-2r^2) = 0r^2 \]

2. Combine the \(r\) terms: \[ -3r + 3r = 0r \]

3. Combine the constant terms: \[ 4 + 6 = 10 \]

Now, putting it all together, we have:

\[ 0r^2 + 0r + 10 = 10 \]

Thus, the sum of the two polynomial expressions is \(10\).