N30°E---- > 60° in standard notation
N 60°E --- > 30°
so .... I read
9 m/s [N30°E] and 2 m/s [N 60°E]
as
(9cos60°, 9sin60°) + (2cos30°, 2sin30°)
= (9(1/2), 9(√3/2) ) + (2(√3/2), 2(1/2) )
= ....
do b) in the same way
Add the following vectors using the Component law.
a. 9 m/s [N30°E] and 2 m/s [N 60°E].
b. 3 N in a direction 15° south of west and 4 N in a direction 12° east of south.
3 answers
N and E +ve
measure angles from E (0 deg) clockwise
assuming 3 N and 4 N are forces in Newtons
W (180 deg) + 15 deg S (clockwise) = 195 deg
S (270 deg) + 12 deg E (clockwise) = 282 deg
Rx = 3 cos 195 + 4 cos 282
Ry = 3 sin 195 + 4 sin 282
measure angles from E (0 deg) clockwise
assuming 3 N and 4 N are forces in Newtons
W (180 deg) + 15 deg S (clockwise) = 195 deg
S (270 deg) + 12 deg E (clockwise) = 282 deg
Rx = 3 cos 195 + 4 cos 282
Ry = 3 sin 195 + 4 sin 282
@Reiny, is the correct way of approaching or nah?
(3cos12°, 3sin12°) + (4cos15°, 4sin15°)
(3cos12°, 3sin12°) + (4cos15°, 4sin15°)