<-4cos15°+4sin12°, -4sin15°-3cos12°> = <-3.03,-3.97>
or approximately <-3,-4> = 5 @ S36.8°W
Add the following vectors using components.
3 N in a direction 15° south of west and 4 N in a direction 12° east of south
2 answers
All angles are measured CCW from +X-axis.
Fr = 3N[195o] + 4N[282o] .
X = 3*Cos195 + 4*Cos282 = -2.07 N.
Y = 3*sin195 + 4*sin282 = -4.69 N.
Fr = sqrt(X^2 + Y^2) = 5.13 N. = Resultant force.
TanA = Y/X, A = 66.2o S. of W. = 246.2o CCW.
Fr = 3N[195o] + 4N[282o] .
X = 3*Cos195 + 4*Cos282 = -2.07 N.
Y = 3*sin195 + 4*sin282 = -4.69 N.
Fr = sqrt(X^2 + Y^2) = 5.13 N. = Resultant force.
TanA = Y/X, A = 66.2o S. of W. = 246.2o CCW.
3 answers