Let's go through the steps to solve the equation you provided.
Starting with the original equation:
\[ 2h - 6 = -3h - 5 \]
You want to add 6 to both sides to eliminate the -6 on the left:
\[ 2h - 6 + 6 = -3h - 5 + 6 \]
This simplifies to:
\[ 2h = -3h + 1 \]
Next, add \(3h\) to both sides to get all terms involving \(h\) on the left:
\[ 2h + 3h = -3h + 3h + 1 \]
This simplifies to:
\[ 5h = 1 \]
If you were to add \(6\) to both sides (as part of another operation), it would look like:
From the equation \(5h = 1\):
If you want to add \(6\) to both sides:
\[ 5h + 6 = 1 + 6 \]
This simplifies to:
\[ 5h + 6 = 7 \]
So, you have correctly performed operations to isolate \(5h\) on one side, but now we see it could represent separate steps, confirming \(5h = 1\) and then adding \(6\).
If you are looking for the final line from the first steps, that should result in: \[ 5h = 1 \rightarrow 5h + 6 = 7 \] but if you simply want the previous without adding:
Final statement of the isolated variable is: \[ 5h = 1 \]
Let me know if you need further steps!