ACD is a right triangle and line segment BE is parallel to the line segment CD. Where B is a point on side AC and E is a point on AD.
AB = 5 cm, BE = 3cm and CD = 9 cm
What is the perimeter of triangle ACD to the nearest tenth of a unit?
Here, Kindly explain how triangle ACD is similar to triangle ABE????
2 answers
which are the right angles?
Whether the triangle is right-angled or not, since BE || CD, you have
2 pairs of angles equal, so the third angle pair must be equal
This makes the triangles similar by definition.
I made a sketch with your information and
AD/9 = 5/3
AD = 15, which makes DE = 10
As it stands, we cannot find the perimeter, since we know nothing about
the length of either AB or AC
If we know it is right-angles, and the question by "Anonymous" is valid,
then we could use Pythagoras to find those sides and then
you can find the perimeter.
2 pairs of angles equal, so the third angle pair must be equal
This makes the triangles similar by definition.
I made a sketch with your information and
AD/9 = 5/3
AD = 15, which makes DE = 10
As it stands, we cannot find the perimeter, since we know nothing about
the length of either AB or AC
If we know it is right-angles, and the question by "Anonymous" is valid,
then we could use Pythagoras to find those sides and then
you can find the perimeter.
1 answer