Acceleration Quick Check

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Question
A net force of 0.7 N is applied on a body. What happens to the acceleration of the body in a second trial if half of the net force is applied?(1 point)
Responses

The acceleration is half of its original value.
The acceleration is half of its original value.

The acceleration is double its original value.
The acceleration is double its original value.

The acceleration is the square of its original value.
The acceleration is the square of its original value.

The acceleration remains the same.

1 answer

To determine how the acceleration of the body changes when half of the net force is applied, we can use Newton's second law of motion, which states:

\[ F = m \cdot a \]

where:

  • \( F \) is the net force applied,
  • \( m \) is the mass of the body, and
  • \( a \) is the acceleration.

In the first trial, if the net force is \( 0.7 , N \), we can express the acceleration as:

\[ a_1 = \frac{F_1}{m} = \frac{0.7 , N}{m} \]

In the second trial, if half of the net force is applied (\( 0.7 , N / 2 = 0.35 , N \)), the new acceleration will be:

\[ a_2 = \frac{F_2}{m} = \frac{0.35 , N}{m} = \frac{0.7 , N}{2m} = \frac{a_1}{2} \]

Thus, the acceleration in the second trial is half of its original value.

The correct response is:

The acceleration is half of its original value.