To find the acceleration when a net force of 20.0 N is applied to a mass of 5.0 kg, we can use Newton's second law of motion, which states that:
\[ F = m \cdot a \]
Where:
- \( F \) is the net force applied,
- \( m \) is the mass of the object,
- \( a \) is the acceleration.
From the information given in the data table:
-
For the first row:
- Net Force = 5.0 N, Mass = 5.0 kg
- Using \( F = m \cdot a \): \( a = \frac{F}{m} = \frac{5.0,N}{5.0,kg} = 1.0,m/s^2 \)
-
For the second row:
- Net Force = 10.0 N, Mass = 5.0 kg
- \( a = \frac{10.0,N}{5.0,kg} = 2.0,m/s^2 \)
-
For the third row:
- Net Force = 20.0 N, Mass = 5.0 kg
- \( a = \frac{20.0,N}{5.0,kg} = 4.0,m/s^2 \)
So, the last cell's value for acceleration when the net force is 20.0 N would be 4.0 m/s².
The correct response is: 4.0.