ABC is a equilateral triangle of side 0.03m. Charges of +5nC and -5nC are placed at the corner A and C find the resultent electric intensity at B.

Answer 1

y components cancel.
From A:
kq/r^2 cos 60 in positive x direction
From C:
kq/r^2 cos 60 in positive x direction
So save time:
E = 2kq cos60/r^2

Answer 2

ABC is an equilateral triangle of side 0.03m charges of +5nc ,+3nc and +5nc

Answer 3

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