The magnitude of the force between two point charges can be calculated using Coulomb's law:
F = k * |q1 * q2| / r^2
where F is the force, k is the Coulomb constant (8.99 x 10^9 N m^2/C^2), q1 and q2 are the charges, and r is the distance between the charges.
In this case, the distance between each corner of the equilateral triangle is 2m. Therefore, the force between each pair of charges is:
F = (8.99 x 10^9) * (8uC * 8uC) / (2m)^2 = 287.52 N
Since all three charges are identical and equally spaced on the triangle, the forces between each pair of charges will have the same magnitude of 287.52 N.
To find the net force on any one of the charges, we need to consider the vector sum of the forces. Since the forces are acting in different directions (towards the other charges), we need to calculate the x and y components of each force and add them together to find the net force.
Since the charges are symmetrically placed, the x and y components will cancel each other out. Therefore, the net force acting on any one of the charges will be 0 N in magnitude.
In conclusion, the magnitude of the forces between each pair of charges is 287.52 N, but the net force acting on any one of the charges is 0 N.
Equal charges of 8uc are placed of the three corners of an equilateral triangle 2m on a side calculated the magnitude and direction of the forces on of the charges
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