AB has endpoints A(-3,2) and B (3,-2)

Question

Find the coordinates of the midpoint of AB

Find AB to the nearest tenth.

Answer 1

A ( - 3 , 2 ) mean :

xA = - 3

yA = 2

B ( 3 , - 2 ) mean :

xB = 3

yB = 2

x- coordinate of midpoint :

xmid = ( xB + xA ) / 2

xmid = ( - 3 + 3 ) / 2 = 0

y- coordinate of midpoint :

ymid = ( yB + yA ) / 2

ymid = ( - 2 + 2 ) / 2 = 0

Coordinates of the midpoint : ( 0 , 0 )

AB = sqrt [ ( xB - xA ) ^ 2 + ( yB - yA ) ^ 2 ]

AB = sqrt [ ( 3 - ( - 3 ) ) ^ 2 + ( - 2 - 2 ) ^ 2 ]

AB = sqrt [ ( 3 + 3) ) ^ 2 + ( - 2 - 2 ) ^ 2 ]

AB = sqrt [ 6 ^ 2 + ( - 4 ) ^ 2 ]

AB = sqrt ( 36 + 16 )

AB = sqrt ( 52 )

AB = 7.2111

AB = 7.2

to the nearest tenth