AB ∥ DC, DE ⊥ AB , AD = BC, m∠ADC = 134° AD = 40, DC = 32, ABCD is a trapezoid. Find: Area of ABCD

Answer 1

m∠DAE = 180-134 = 46
sin 46 = DE/40
DE =40 sin 46
area = 32 * 40 sin 46