We already discussed the fact that the vertical motion can be solved separately from the constant horizontal speed motion
THERE IS NO DIFFERENCE between A and B
vertical problem:
a = -g = -9.81 m/s^2
v = Vi + a t = -9.81 t = -9.81*3 = - 39.4 m/s
h = Hi + Vi t - 4.9 t^2
h = Hi + 0 - 4.9* 9 = Hi - 44.1
so
Hi initial height - h height at 3 seconds = distance fallen = 44.1 meters
A)You drop a stone from a position of rest.
How far will it fall vertically in the first 3 s?
The acceleration of gravity is 9.8 m/s
Answer in units of m
B)If you instead toss it horizontally at 1.8 m/s,
how far will it fall vertically in the first 3 s?
2 answers
Damon, your answer is wrong
2 answers