a. Write and balance the equation for the reaction of calcium carbonate with hydrochloric acid, then answer the following questions.

b. What mass of calcium carbonate is required to neutralize 83.5mL of 6.00M HCl?

does the balanced equation have any significance in this problem and for b. im not sure how to start it

1 answer

CaCO3 + 2HCl ==> CaCl2 + H2O + CO2

mols HCl = M HCl x L HCl = ?
Using the coefficients in the balanced equation, convert mols HCl to mols CaCO3. That will be mols HCl x (1 mol CaCO3/2 mols HCl) = mols HCl x 1/2 = ?
Then convert mols CaCO3 to grams. g CaCO3 = mols CaCO3 x molar mass CaCO3.