mols CaCo3 = grams/molar mass.
mols HCl = grams/molar mass.
Convert mols CaCO3 to mols CaCl2 using the coefficients in the balanced equation.
Do the same for mols HCl.
It is likely that these two values for mols CaCl2 will not be the same which means one is not right; the correct one in limiting reagents (this is a limiting reagent problem) is ALWAYS the smaller value and the reagent producing that value is the limiting reagent.
Using the smaller value convert mols CaCl2 to grams. g = mols x molar mass.
P4 is the same thing; however, you didn't ask a question for #2.
1)The following balanced chemical equation represents the reaction of calcium carbonate CaCO3 (s), with hydrochloric acid :
CaCo3(s) + 2HCl (aq) -> CaCl2(aq) + CO2(g) + H2O(l)
If 155 g of calcium carbonate reacts with 245 g of hydrochloric acid, what mass of calcium chloride, CaCl2(s), is produced?
2). The reaction between solid white phosphorus, P4(s), and oxygen gas produces solid tetraphosphorus decoxide that is formed when 25.0g of solid white phosphorus and 50.0 g of oxygen are combined.
Show all your steps please...
1 answer