A worker drags a crate across a factory floor by pulling on a rope tiedto the crate. The worker exerts a force of 450 N on the rope, which is inclined at 38 degrees to the horizontal and the floor exerts a horizontal force of 125 N that opposes the motion. Calculate the magnitude of the acceleration of the crate if a)its mass is 310kg and b) its weight is 310 N.
How would I find the acceleration with the given information?
a = F/m
To get the acceleration (in m/s^2), divide the resultant force (in N) along the floor by the mass (in kg).
The resultant force along the floor is
450 N* cos 38 - 125 N
You do the rest
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