(1/2) m v^2 = m g h
so
v = sqrt ( 2 g h )
A worker at the top of a 600-m-tall television transmitting tower accidentally drops a heavy tool. If air resistance is negligible, how fast (in m/s) is the tool going just before it hits the ground?
2 answers
V^2 = Vo^2+2g*h = 0+19.6*800 = 15680
V = 125 m/s.
V = 125 m/s.