A woman weighs Fg= 600 N when standing on a stationary scale. Now, the woman is riding an elevator from the 1st floor to the 10th floor. As the elevator approaches the 10th floor, it decreases its upward speed from 7 m/s to 1 m/s in a time interval of 1 s. What is the average force exerted by the elevator floor on this woman during this 1 s interval? Use g=10 m/s2.
a) 360N
b) 120N
c) 180N
d) 240N
e) 480N
3 answers
240 for ur values
can someone elaborate on this problem, i have diferent values
a = (v - v0)/t = (1 m/s - 5 m/s)/(1 s) = -4 m/s^2
F = ma
N - mg = ma
N = m(a+g)
N = (w/g)(a+g)
N = w(a/g + 1)
N = (500 N)(-4 m/s^2 / 10 m/s^2 + 1) = 300 N
F = ma
N - mg = ma
N = m(a+g)
N = (w/g)(a+g)
N = w(a/g + 1)
N = (500 N)(-4 m/s^2 / 10 m/s^2 + 1) = 300 N
7 answers