A woman on a bridge 75.0m high sees a raft floating at a constant speed on the river below. She drops a stone from rest in an attempt to hit the raft. The stone is released when the raft has 7.00m more to travel before passing under the bridge. The stone hits the water 4.00m in front of the raft. Find the speed of the raft.

Full steps please

1 answer

d = 0.5g*t^2 = 75
4.9t^2 = 75
t^2 = 15.31
Tf = 3.912 s. = Fall time.

d = V*Tf = 7-4 = 3 m.
V * 3.912 = 3
V = 0.769 m/s.