so far i have 4.47m distance boat travels
y=1/2 at^2
t= /2(-104m)|(-___m/s^2)=?
trying to find the time it takes the stone to fall
A woman on a bridge 104 m high sees a raft floating at a constant speed on the river below. She drops a stone from rest in an attempt to hit the raft. The stone is released when the raft has 9.78 m more to travel before passing under the bridge. The stone hits the water 5.31 m in front of the raft. Find the speed of the raft.
2 answers
104 = (1/2)(9.8)t^2
t^2 = 208/9.8 = 21.2
t = 4.67 seconds
t^2 = 208/9.8 = 21.2
t = 4.67 seconds