a. a = (11.3-0)/3.72 = 3.04 m/s^2.
b. d = 0.5*3.04*(3.72)^2 = 21.0 m.
(a) What is the magnitude of the average acceleration of a skier who, starting from rest, reaches a speed of 11.3 m/s when going down a slope for 3.72 s? (b) How far does the skier travel in this time?
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