What is the magnitude of the average acceleration of a skier who, starting from rest, reaches a speed of 8.0 m/s when going down a slope for 5.0 s? How far does the skier travel in this time?

Answer 1

a = change in speed/ change in time
= (8-0)/5 = 1.6 m/s^2
d = (1/2) a t^2 = .5*1.6*25 = 20 meters
or alternatively
average speed = 4 m/s * 5 s = 20 meters