(a) what Is the density of an object that is 14% submerged when floating in water at 0 degrees Celsius? (b) what percentage of the object will be submerged if it is placed in ethanol at 0 degrees Celsius?

Answer 1

d1*V1 = d2*V2

where d1 and V1 are the density and volume of object 1; d1 and V2 are the density and volume of the fluid

Then V2 = 0.14*V1

d1*V1 = d2*0.14*V1
d1 = d2*0.14

Look up the density of water at 0 degrees C (= d2). Solve for d1

b) d1*V1 = d2*V2

You know d1 from a. You can look up the the density of ethanol, d2.

% submerged = V2/V1 = d1/d2