Asked by Christina
A weight of 50.0 N is hung from the center of a stretched horizontal wire 10.0 meters long. It causes the wire to say 1.00m at its center. What is the force exerted by each half of the wire in supporting the weight?
Answers
Answered by
bobpursley
1. due to symettry, assume each half is supporting 25N
So you are looking for tension.
SinTheta=1m/5m based on lengths
SinTheta=25N/tension based of forces
25/Tension=1/5
tension= 125N
check that.
So you are looking for tension.
SinTheta=1m/5m based on lengths
SinTheta=25N/tension based of forces
25/Tension=1/5
tension= 125N
check that.
Answered by
Christina
Thank you so so much And I also posted another physics question down below if you don't mind helping me out?
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