A weight of 50.0 N is hung from the center of a stretched horizontal wire 10.0 meters long. It causes the wire to say 1.00m at its center. What is the force exerted by each half of the wire in supporting the weight?

Answer 1

1. due to symettry, assume each half is supporting 25N

So you are looking for tension.

SinTheta=1m/5m based on lengths

SinTheta=25N/tension based of forces

25/Tension=1/5
tension= 125N
check that.

Answer 2

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