To find the tensions in wires T1 and T2, we can use the principles of equilibrium, which state that the net force and net torque acting on a system are zero.
First, let's assume that the weight of each wire is negligible compared to the other forces involved. This assumption allows us to consider only the tensions in the wires and the weight of the central object.
To find the tension in wire T1, we can consider the forces acting in the horizontal direction. Since wire T1 is horizontal, its tension only acts vertically. Therefore, the tension in T1 is equal to the weight of the central object, which is 40 kg multiplied by the acceleration due to gravity (9.8 m/s^2):
T1 = (40 kg)(9.8 m/s^2) = 392 N
Next, let's find the tension in wire T2. We can consider the forces acting in the vertical direction. The vertical component of the tension in T2 counteracts the weight of the central object (40 kg) and the weight of the central weight (177 N). Thus, we can write the equation:
T2cos(53°) = (40 kg + 177 N)
T2 = (40 kg + 177 N)/cos(53°)
Using a calculator, we can find the value of T2.
Please note that the diagram you mentioned would be helpful to visualize the arrangement of the wires and objects accurately.