While I can't access external links like Desmos, I can help you understand how to formulate the answers based on a hypothetical scenario of a water tank being drained.
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Initial amount of water: If the tank started with a certain amount of water, this would represent the y-intercept of the line graphed. For example, if the tank initially had 500 liters of water, that would be the y-intercept (0, 500).
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Time to empty the tank: If the tank is empty after a certain period, this would represent the x-intercept of the line graphed. Continuing from the previous example, if the tank takes 10 hours to empty, the x-intercept could be (10, 0).
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Rate of drainage: The rate at which the tank is emptying, say 50 liters per hour, represents the negative slope of the line graphed (assuming downward slope). If the tank initially had 500 liters and drained to empty in 10 hours, the slope (m) can be calculated as: \[ m = \frac{\text{change in y}}{\text{change in x}} = \frac{0 - 500}{10 - 0} = \frac{-500}{10} = -50 \text{ liters per hour} \]
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Equation of the line: To create the equation representing this scenario, you can use the slope-intercept form of a linear equation \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept. Using the earlier example: \[ y = -50x + 500 \] Here, \(y\) represents the volume of water in the tank at time \(x\) hours.
With these points in mind, you can substitute the numbers accordingly based on the actual values you see on the Desmos graph.
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