To analyze the situation with the water tank's draining process, let's address each part of your question step-by-step.
-
Initial Amount of Water: The tank starts with water at the point (0, 35). This means that when \( x = 0 \) (at time 0 hours), the amount of water in the tank was 35 gallons. Therefore, the tank had 35 gallons of water when it started being drained. This represents the y-intercept of the line graph (the value of \( y \) when \( x = 0 \)).
-
Rate of Emptying: To find the rate at which the tank is emptying, we can calculate the slope of the line represented by the points.
First, we need to determine the change in gallons per hour. We can take two points on the line: (0, 35) and (11.5, 0).
\[ \text{Slope} = \frac{\text{Change in } y}{\text{Change in } x} = \frac{0 - 35}{11.5 - 0} = \frac{-35}{11.5} \approx -3.04 \]
This means the tank is emptying at a rate of approximately 3.04 gallons per hour. This represents the slope of the line.
-
Equation of the Line: The slope-intercept form of a line is given by the equation:
\[ y = mx + b \]
Where \( m \) is the slope and \( b \) is the y-intercept. Here, \( m \approx -3.04 \) and \( b = 35 \).
Therefore, the equation that would represent this scenario would be:
\[ y = -3.04x + 35 \]
In summary:
- The tank had 35 gallons of water when it started being drained; this represents the y-intercept.
- The tank is emptying at a rate of 3.04 gallons per hour; this represents the slope.
- The equation that would represent this scenario would be \( y = -3.04x + 35 \).