192 = 112 t - 16 t^2
or
16 t^2 - 112 t + 192 = 0
t = [ 112 +/- sqrt ( 12544 - 12288)]/32
t = [112 +/- 16 ]/ 32
t = 3 seconds on the way up
and
t = 4 seconds on the way down
a water rocket is launched with an initial velocity of 112ft/sec. its height h, in feet T seconds is given by the formula h=112T-16T^2. when will the rocket be exactly 192 ft above the ground?
the rocket first reaches a height of 192ft after _____ and reaches 192ft a second time after____.
thank you!
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