Asked by Anonymous
A rocket is launched from the top of a 50 foot cliff with an initial velocity of 120 feet per second. The height, h, of the rocket after t seconds is given by the equation h=-16t^2 + 120t+ 50. How long after the rocket is launched will it be 10 feet from the ground?
Answers
Answered by
Steve
just solve for t in
-16t^2 + 120t+ 50 = 10
probably the quadratic formula will be helpful.
-16t^2 + 120t+ 50 = 10
probably the quadratic formula will be helpful.
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