A kL is 1 meter^3
density of water is 1000 kg/m^3
potential energy gained in one hour = m g h = 9 *1000 *9.81 * 70
= 6,180,300 Joules / hr
divide by 60 to get Joules /minute = 103,005 Joules/minute
by the way
divide by 60 again to get Joules per second or watts
= 1717 watts =1.7 kW
so the motor / pump system is around 50% efficient
A water pump produces 9kl of water per hour at height of 70m above the pump. The pump is driven by 3kW electric motor calculate
1.the work done per hour.
2.the work done per minute.
2 answers
1. m * g * h ... 9000 kg * 9.8 m/s^2 * 70 m Joules
2. divide #1 by 60
2. divide #1 by 60
2 answers