A water balloon with a mass of 1.20 kg is falling from a roof. If the average force of friction is 0.500 N, what is the acceleration on the balloon in m/s2?

Question

A water balloon with a mass of 1.20 kg is falling from a roof.  If the average force of friction is 0.500 N, what is the acceleration on the balloon in m/s2?

I am not sure how to get started

mssailormouth · Answer

1.20kg x 9.80 m/s^2= 11.76-0.500=11.26 11.26=1.20a a=9.38 m/s^2??

oobleck · Answer

looks good to me

Damon · Answer

Yes, but not sure I would say it that way Fdown = m a down mg - .5 = ma a = (mg -.5)/m = (1.2*9.8 - .5) / 1.2 = 11.26/1.2 = 9.38 down