A wallet contains $445 in $5, $10, and $20 bills.

The number of $5 bills exceeds the number of $10 bills by 2, and the number of $20 bills is 3 less than twice the number of $10 bills.
How many bills of each type are there?

1 answer

number of tens ---- x
number of fives ---- x+2
number of twenties -- 2x-3

value equation:
10x + 5(x+2) + 20(2x-3) = 445
10x + 5x + 10 + 40x - 60 = 445
55x = 495
x = 9

sub into my definitions ...