speed of rock = 15.5 , mass = .32
speed of wagon = v , mass = 92.7
initial momentum = 93 * .52 = 48.4
final momentum = initial momentum
so
48.4 = .32*15.5 + 92.7*v
solve for v
if backward
48.4 = -.32*15.5 + 92.7*v
A wagon is rolling forward on level ground. Friction is negligible. The person sitting in the wagon is holding a rock. The total mass of the wagon, rider, and rock is 93.0 kg. The mass of the rock is 0.320 kg. Initially the wagon is rolling forward at a speed of 0.520 m/s. Then the person throws the rock with a speed of 15.5 m/s. Both speeds are relative to the ground. Find the speed of the wagon after the rock is thrown directly forward.
m/s
Find the speed of the wagon after the rock is thrown directly backward.
m/s
1 answer
1 answer