A child pulls a wagon by the handle along a flat sidewalk. She exerts a force of 80.0 N at an angle of 30.0 above the horizontal while she moves the wagon 12 m forward. The force of friction on the wagon is 34 N.
Calculate the mechanical work done by the child on the wagon
Calculate the total work done on the wagon
3 answers
asd
Force/F= 80N
Angle=30 degrees
Distance/deltad=12m
Friction Force/Ff=34N
(a) W = Fcos(30)d
W = (80N)(cos30)(12m)
W = 831.38J
Angle=30 degrees
Distance/deltad=12m
Friction Force/Ff=34N
(a) W = Fcos(30)d
W = (80N)(cos30)(12m)
W = 831.38J
W = 831.38J
Ff = 34N
deltad = 12m
(b) W + (Ff x 12m)
= W + (-34N x 12m)
= 831.38J + (-408)
= 831.38J - 408
= 423.38J
Ff = 34N
deltad = 12m
(b) W + (Ff x 12m)
= W + (-34N x 12m)
= 831.38J + (-408)
= 831.38J - 408
= 423.38J