Question

A volunteer ambulance service handles 0 to 5 service calls on any given day. The probability distribution for the number of service calls is as follows: one column has number of service calls (X) those numbers are 0 1 2 3 4 5. The next column Probability P (X) those numbers are 0.08, 0.16, 0.27, 0.2, 0.15, 0.14. The next column is X*P(X), the next column (X-meuh)next column (X-meuh)to the second power, then P(X)* (X-meuh) to the second power. The questions are: What is the mean number of service calls. Next question What is the variance of service calls.What is the standard deviation. I'm stuck on the process between each column to get the answers, this is set up as a chart. Help please this is my exam😱