Pb ==> Pb^2+ + 2e
2Ag^+ + 2e ==> 2Ag
--------------------
Pb + 2Ag^+ ==> Pb^2+ + 2Ag
Pb(s)|Pb^2+||Ag^+|Ag(s)
Pb is -; Ag is +
A voltaic cell is constructed with an Ag/Ag+ half-cell and a Pb/Pb2+ half-cell. Measurement shows that thesilver electrode is positive.
-Write balanced half-reactions and the overall spontaneous reaction.
3 answers
redox eq
Ag^+(aq)+e^- >>> Ag(s)
Oxidation Eq
Pb(s) >>> Pb^2+(aq)+2e^-
overall
2Ag^+(aq)+Pb(s) >>> Pb^2+(aq)+2Ag(s)
Ag^+(aq)+e^- >>> Ag(s)
Oxidation Eq
Pb(s) >>> Pb^2+(aq)+2e^-
overall
2Ag^+(aq)+Pb(s) >>> Pb^2+(aq)+2Ag(s)
yes
3 answers