You want the vibrating part of the stng to be 440/523 of the original length, to decrease the wavelngth by that factor. (The frequency will be higher by the inverse factor 523/440.)
440/523 x 32.8 = 27.6 cm. The finger should be moved 32.8 - 27.6 = 5.2 cm from the end of the string.
A violin string has a standard length of 32.8 cm. It sounds the musical note A (440Hz) when played without fingering.
How far from the end of the string should you place your finger to play the note C (523Hz)? answer should be in cm.
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